Error When Calling The Metaclass Bases Python
What is a type system? I have amateur level experience in python. Can an ATCo refuse to give service to an aircraft based on moral grounds? Developing web applications for long lifespan (20+ years) Digital Diversity Using Java's Stream.reduce() to calculate sum of powers gives unexpected result How to convert a set of sequential integers into a Check This Out
Error When Calling Metaclass Bases
more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Linked 2 why class creation throws error Related 1Django Gunicorn: Error when calling the metaclass bases295Creating a singleton in Python4Metaclass conflict, multiple inheritance, and instance as parent4metaclass error: type.__init__() takes 1 I'm using python 2.7.10 to follow a flask tutorial being delivered using python 3.4.
So assuming I need C to be the metaclass of B and B will be a subclass of A can someone tell me what is going wrong here and how I share|improve this answer answered May 25 at 8:58 Daniel Roseman 321k24403489 Thank you. from UIMap import tomcat8LoginPage,tomcat8urls,competitors class test_Competitors(unittest): def setup(self, driver): self.driver = driver self.driver = webdriver.Firefox() self.driver.get("https://qa-tomcat8.ez-touch.net/acton/account/login.jsp") def test_Compete(self): driver = self.driver actions = ActionChains(driver) ### Log-in and navigate to Competitors page Error When Calling The Metaclass Bases Module.__init__() Takes At Most 2 Arguments Why is it refering to *module*.__init__?
python class inheritance metaclass share|improve this question asked Feb 9 '10 at 18:24 David Underhill 11.4k44258 add a comment| 3 Answers 3 active oldest votes up vote 46 down vote accepted Error When Calling The Metaclass Bases Cannot Create A Consistent Method Resolution Using \ for line continuation is very much against best practices in Python –Peter Masiar Feb 14 '15 at 1:01 I mean self.method(a, b) has 3 arguments: self, a, This meant that my class had the same name as the module. All set! –papu May 25 at 13:57 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign
Error When Calling The Metaclass Bases Youtube
How do I answer why I want to join a smaller company given I have worked at larger ones? If it is a metaclass, I would be surprised if there weren't any docs explaining its use. Error When Calling Metaclass Bases vBulletin ©2000 - 2016, Jelsoft Enterprises Ltd. Error When Opening Internet Explorer The default metaclass, in the absence of any indication otherwise, is class type.
Did Sputnik 1 have attitude control? his comment is here In particular, it sees that type(UxerDict) is Module, not type. from a import A class B (A): ... Is intelligence the "natural" product of evolution? Error When Calling The Metaclass Bases Takes At Most 2 Arguments
And what about "double-click"? Not the answer you're looking for? A simple script: Code: from xmms import control class hello: __metaclass__ = control def hellomethod(self): print "hello" hello().hellomethod() produces the following error: Code: Traceback (most recent call last): File "hello.py", line this contact form Not the answer you're looking for?
The module "UserDict" contains the class "UserDict". Typeerror Error When Calling The Metaclass Bases Object() Takes No Parameters If Dumbledore is the most powerful wizard (allegedly), why would he work at a glorified boarding school? get that funky error...
Have a feeling its got something to do with class definition, but unable to nail it.
Can anyone tell me what I'm doing wrong? Traceback (most recent call last): File "
Posted by: Account Deleted | April 25, 2010 at 01:09 AM And it turns out that there is another case in which this error is generated: where you thought you defined You're importing the module "UserDict" and then trying to create a subclass of it. You need to inherit from object: class Obstacle(object) In Python 3, there is no difference and it should be fine. -- Steven Previous message: [Tutor] inheritance and super() function in python Hot Network Questions Can two integer polynomials touch in an irrational point?
How to get this substring on bash script? A module in Python is a convenient place to define names where they won't interfere with other names. current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. The former is a module, the latter is the class, which is what you should be inheriting from.
Traceback (most recent call last): File "